document.write( "Question 410181: HELLO: A 35% acid solution needs to be mixed with a 70% solution to create a 20 liter mixture that is 40% acidic. How many of each solution is required?\r
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document.write( "Howard Wilcox
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document.write( "howdywilcox@comcast.net \n" );
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Algebra.Com's Answer #288529 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .70x+.35(20-x)=.40*20 \n" ); document.write( ".70x+7-.35x=8 \n" ); document.write( ".35x=8-7 \n" ); document.write( ".35x=1 \n" ); document.write( "x=1/.35 \n" ); document.write( "x=2.857 liters of the 70% solution is used. \n" ); document.write( "20-2.857=17.143 liters of 35% solution is used. \n" ); document.write( "Proof: \n" ); document.write( ".70*2.857+.35*17.143=.40*20 \n" ); document.write( "2+6=8 \n" ); document.write( "8=8 \n" ); document.write( " |