document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=410222>Question 410222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the line through points (-1,6) and (x,2) is perpendicular to the graph of 2x + y = 3.  Find the value of x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288520 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288520\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose the line through points (-1,6) and (x,2) is perpendicular to the graph of 2x + y = 3.  Find the value of x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Find slope of<BR>\n" );
document.write( "2x + y = 3<BR>\n" );
document.write( "by rearranging into the \"slope-intercept\" form:<BR>\n" );
document.write( "2x + y = 3<BR>\n" );
document.write( "y = -2x + 3<BR>\n" );
document.write( "slope then, is -2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "A line perpendicular to this must have a slope that is the \"negative reciprocal\":<BR>\n" );
document.write( "-2m = -1<BR>\n" );
document.write( "m = 1/2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "slope of (-1,6) and (x,2)<BR>\n" );
document.write( "(y2-y1)/(x2-x1) = 1/2<BR>\n" );
document.write( "(2-(-6))/(x-(-1)) = 1/2<BR>\n" );
document.write( "(2+6)/(x+1) = 1/2<BR>\n" );
document.write( "8/(x+1) = 1/2<BR>\n" );
document.write( "cross-multiply:<BR>\n" );
document.write( "16 = x+1<BR>\n" );
document.write( "15 = x\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
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