document.write( "Question 410167: How many liters of a 20% acid solution must be added to 100 liters of a 50% acid solution to get a 40% solution? \n" ); document.write( "

Algebra.Com's Answer #288500 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"a\"$ = liters of 20% solution needed
\n" ); document.write( "given:
\n" ); document.write( " $\".2a\"$ = liters of acid in 20% solution
\n" ); document.write( " $\".5%2A100+=+50\"$ = liters of acid in 50% solution
\n" ); document.write( " $\"%28.2a+%2B+50%29+%2F+%28100+%2B+a%29+=+.4\"$
\n" ); document.write( " $\".2a+%2B+50+=+.4%2A%28100+%2B+a%29\"$
\n" ); document.write( " $\".2a+%2B+50+=+40+%2B+.4a\"$
\n" ); document.write( " $\".2a+=+10\"$
\n" ); document.write( " $\"a+=+50\"$
\n" ); document.write( "50 liters of 20% solution must be added
\n" ); document.write( "check:
\n" ); document.write( " $\"%28.2%2A50+%2B+50%29+%2F+%28100+%2B+50%29+=+.4\"$
\n" ); document.write( " $\"60%2F150+=+.4\"$
\n" ); document.write( " $\"60+=+60\"$
\n" ); document.write( "OK \n" ); document.write( "

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