document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=410126>Question 410126</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the center and radius of the graph of the circle. The equation of the circle is written in general form. <BR>\n" );
document.write( "x2 + y2 &#8722; 10x &#8722; 4y + 4 = 0 \r<BR>\n" );
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document.write( "center      (x, y)  =  ? <BR>\n" );
document.write( "radius:         ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288491 by </B><A HREF=/tutors/aboutme.mpl?userid=Coyote+10><B>Coyote 10(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Coyote+10><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288491\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First group the x and y terms together so you get x^2-10x+y^2-4y+4=0.Subtract four to the right side. Complete the square for both the x and y terms and add both constances to the right side:(x-5)^2+(y-2)^2= -4+25+4. Thus your equation would be (x+5)^2+(y-2)^2=25.When you suqare both sides you get (x+5)+(y-2)=5. Your center would (-5,2), h=-5 and k=2. Your radius would equal 5   </SPAN>\n" );
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