document.write( "Question 409375: log(x)+log(x)=2
\n" ); document.write( "I'm not exactly sure what to do on this one. \n" ); document.write( "

Algebra.Com's Answer #288481 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
log(x) + log(x) = 2
\n" ); document.write( "The fast way to solve this is to add the terms together. Logarithmic terms are like terms if their bases and arguments are the same. This is certainly true here. And adding one log(x) to another log(x) gives us:
\n" ); document.write( "2log(x) = 2
\n" ); document.write( "Dividing both sides by 2 we get:
\n" ); document.write( "log(x) = 1
\n" ); document.write( "At this point, if you understand what logarithms are, you probably already know the answer. If not, we rewrite the equation in exponential form. In general $\"log%28a%2C+%28p%29%29+=+q\"$ is equivalent to $\"p+=+a%5Eq\"$ . Using this pattern on your equaiton we get:
\n" ); document.write( " $\"x+=+10%5E1\"$
\n" ); document.write( "which simplifies to:
\n" ); document.write( "x = 10
\n" ); document.write( " \n" ); document.write( "

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