document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=410020>Question 410020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve the following problem. x+3y=1 -3x-3y=-15<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288446 by </B><A HREF=/tutors/aboutme.mpl?userid=Adrish><B>Adrish(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adrish><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SOLUTIONS: x+3y=1.............(1)\r<BR>\n" );
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document.write( "-3x-3y=-15.................(2)<BR>\n" );
document.write( "Equation (1) can be rewritten as<BR>\n" );
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document.write( "  x=-3y+1\r<BR>\n" );
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document.write( "Now Divide the whole equation(2) by -3, we get\r<BR>\n" );
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document.write( "x+y=5<BR>\n" );
document.write( "Substitute the value of x in the above equation we get\r<BR>\n" );
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document.write( "-3y+1+y=5<BR>\n" );
document.write( "-2y = 4<BR>\n" );
document.write( "so, y=-2\r<BR>\n" );
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document.write( "Now substitute the value of y in<BR>\n" );
document.write( "x=-3y+1<BR>\n" );
document.write( "x=-3(-2)+1<BR>\n" );
document.write( "x=-5 </SPAN>\n" );
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