document.write( "Question 409819: Can you pls help me with the following:\r
\n" ); document.write( "\n" ); document.write( "Use the Change of Base Formula to evaluate each expression. Leave your answer in \"calculator ready\" format. \r
\n" ); document.write( "\n" ); document.write( "log_2⁡7\r
\n" ); document.write( "\n" ); document.write( "Thank you!!
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Algebra.Com's Answer #288405 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"log%282%2C+%287%29%29\"
\n" ); document.write( "No calculator I know of :knows\" base 2 logarithms. So the only way to express this logarithm in a way that your calculator can handle is to use the Change of Base Formula to change this base 2 logarithm into an expression involving logarithms your calculator does \"know\", like base 10 or base e (aka ln).

\n" ); document.write( "The Change of Base Formula is:
\n" ); document.write( "\"log%28a%2C+%28p%29%29+=+log%28b%2C+%28p%29%29%2Flog%28b%2C+%28a%29%29\"
\n" ); document.write( "We can use this to change to base 2 logarrthm into an expression of base 10 logarithms:
\n" ); document.write( "\"log%28%287%29%29%2Flog%28%282%29%29\"
\n" ); document.write( "or base e logarithms:
\n" ); document.write( "\"ln%287%29%2Fln%282%29\"

\n" ); document.write( "Note: If you actually calculate both of these expressions you will find, believe it or not, that they are equal!
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