document.write( "Question 409903: Can you pls. help:
\n" ); document.write( "Solve the equation, leave your answer in \"calculator ready\" format.\r
\n" ); document.write( "\n" ); document.write( "lne^x=3
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Algebra.Com's Answer #288404 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"ln%28e%5Ex%29+=+3\"
\n" ); document.write( "We start be rewriting this in exponential form. In general \"log%28a%2C+%28p%29%29+=+q\" is equivalent to \"p+=+a%5Eq\". Using this pattern on your expression we get:
\n" ); document.write( "\"e%5Ex+=+e%5E3\"
\n" ); document.write( "The only way these powers of e can be equal is if the exponents themselves are equal, too. So:
\n" ); document.write( "x = 3
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