document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=409919>Question 409919</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for x. \r<BR>\n" );
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document.write( "log3(x+7)=2-log3(x-1) \r<BR>\n" );
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document.write( "Write the exact answer using base-10 logarithms.  \r<BR>\n" );
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document.write( "log3(x+7)=2-log3(x-1) <BR>\n" );
document.write( "log3(x+7) + log3(x-1) = 2 <BR>\n" );
document.write( "log3 [(x+7)/(x-1)] = 2 <BR>\n" );
document.write( "(x+7)(x-1) = 3^2 <BR>\n" );
document.write( "x^2 + 6x - 7 = 9 <BR>\n" );
document.write( "x^2 + 6x - 16 = 0 <BR>\n" );
document.write( "(x+8)(x-2) = 0 <BR>\n" );
document.write( "x = -8 or x = 2 \r<BR>\n" );
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document.write( "but x=-8 would make log3(x+7) undefined, so \r<BR>\n" );
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document.write( "x = 2 \r<BR>\n" );
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document.write( "( why would it ask to use base 10 logs ????)  \r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288400 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288400\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You've done the problem perfectly. I can only guess that the instruction regarding base 10 logarithms applies to a set of problems, some of which may require logarithms to solve. </SPAN>\n" );
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