document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=409853>Question 409853</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the carpenter saws a board that is 22 feet long into two pieces. One piece is to be 1 foot longer than twice the length of the shorter piece. Find the length of each piece. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288382 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the length of the shorter piece x.  Then the longer piece will be 1 + 2x.<BR>\n" );
document.write( "Together they must be 22 feet...the algebra looks like this:\r<BR>\n" );
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document.write( "x + (1 + 2x) = 22<BR>\n" );
document.write( "3x + 1 = 22<BR>\n" );
document.write( "3x = 21<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "2x + 1 = 15<BR>\n" );
document.write( "Your pieces are 7 and 15 feet long.<BR>\n" );
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