document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=409877>Question 409877</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solving systems of equations by substitution<BR>\n" );
document.write( "-5x+y=-2<BR>\n" );
document.write( "-3x+6y=-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288377 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288377\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, let's solve the first one for y and substitute that into the second one<BR>\n" );
document.write( "-5x+y=-2<BR>\n" );
document.write( "-3x+6y=-12<BR>\n" );
document.write( "we get<BR>\n" );
document.write( "y = 5x - 2<BR>\n" );
document.write( "then<BR>\n" );
document.write( "-3x + 6(5x - 2) = -12<BR>\n" );
document.write( "-3x + 30x - 12 = -12<BR>\n" );
document.write( "27x = 0<BR>\n" );
document.write( "x = 0<BR>\n" );
document.write( "back into eqn #1...<BR>\n" );
document.write( "0 + y = -2<BR>\n" );
document.write( "y = -2<BR>\n" );
document.write( "(0, -2) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );