document.write( "Question 409305: give the measure of the supplement of each angle\r
\n" ); document.write( "\n" ); document.write( "1. 47°
\n" ); document.write( "2. 92°
\n" ); document.write( "3. 113°
\n" ); document.write( "4. 27°
\n" ); document.write( "5. 67°
\n" ); document.write( "6. 132°\r
\n" ); document.write( "\n" ); document.write( "give the measure of the complement of each angle\r
\n" ); document.write( "\n" ); document.write( "1. 14°
\n" ); document.write( "2. 40°
\n" ); document.write( "3. 78°
\n" ); document.write( "4. 28°
\n" ); document.write( "5. 90°
\n" ); document.write( "6. 67° \n" ); document.write( "

Algebra.Com's Answer #288364 by richard1234(7193) $\"\"$ $\"About$

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For the first six problems, subtract each angle from 180, i.e. the supplement of 47 degrees is 180 - 47 = 133.\r
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\n" ); document.write( "\n" ); document.write( "For the next six, subtract each angle from 90. \n" ); document.write( "

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