document.write( "Question 409556: Find two integers whose product is 408 such that one of the integers is five less than seven times the other integer. \n" ); document.write( "

Algebra.Com's Answer #288254 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "one of the integers is five less than seven times the other integer.
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document.write( "Let x and (7x-5)represent the intergers
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document.write( "Question states***
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document.write( " x(7x-5) = 408
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document.write( "   7x^2 - 5x -408 = 0
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document.write( "Solving for x\r
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document.write( "   x = 112/14 = 8  and x = -102/14 (extraneous solution as is a non-integer)  
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document.write( "Integers are 8 and 51 (7*8-5)\r
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document.write( "CHECKING our Answer***
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document.write( "   8*51 =408 \n" );
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