document.write( "Question 43875: Solve to four decimal places: log(4) z+log(4)(z-3)=1.\r
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Algebra.Com's Answer #28820 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
log(z) + log(z-3) = 1
\n" ); document.write( "log(z(z-3)) = 1
\n" ); document.write( "\"+z%28z-3%29+=+4%5E1+\"
\n" ); document.write( "z(z-3) = 4
\n" ); document.write( "\"+z%5E2+-+3z+=+4+\"
\n" ); document.write( "\"+z%5E2+-+3z+-+4+=+0+\"
\n" ); document.write( "(z-4)(z+1) = 0
\n" ); document.write( "so z-4=0 or z+1=0
\n" ); document.write( "z=4 or z=-1\r
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\n" ); document.write( "\n" ); document.write( "z=-1 is not a valid answer since log(negative number) is not allowed.\r
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\n" ); document.write( "\n" ); document.write( "So, answer is z=4\r
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\n" ); document.write( "\n" ); document.write( "jon.
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