document.write( "Question 409316: find three consecutive odd integers such that three times the first integer is one less than than the sum of the second and third integers \n" ); document.write( "

Algebra.Com's Answer #288158 by peter_toribio90(6) $\"\"$ $\"About$

You can put this solution on YOUR website!
Three consecutive odd integers:
\n" ); document.write( " $\"x\"$ = first odd integer
\n" ); document.write( " $\"x+%2B+2\"$ = second odd integer
\n" ); document.write( " $\"x+%2B+4\"$ = third odd integer\r
\n" ); document.write( "\n" ); document.write( " $\"3x+=+%28x+%2B+2%29+%2B+%28x+%2B+4%29+-+1\"$
\n" ); document.write( " $\"3x+=+2x+%2B+6+-+1\"$
\n" ); document.write( " $\"3x+=+2x+%2B+5\"$
\n" ); document.write( " $\"3x+-+2x+=+5\"$
\n" ); document.write( " $\"x+=+5\"$ \r
\n" ); document.write( "\n" ); document.write( "first odd integer = $\"x+=+5\"$
\n" ); document.write( "second odd integer = $\"x+%2B+2+=+5+%2B+2+=+7\"$
\n" ); document.write( "third odd intger = $\"x+%2B+4+=+5+%2B+4+=+9\"$ \r
\n" ); document.write( "\n" ); document.write( "The three consecutive odd integers are 5, 7, and 9.\r
\n" ); document.write( "\n" ); document.write( "CHECK.\r
\n" ); document.write( "\n" ); document.write( " $\"3x+=+%28x+%2B+2%29+%2B+%28x+%2B+4%29+-+1\"$
\n" ); document.write( " $\"3%285%29+=+7+%2B+9+-+1\"$
\n" ); document.write( " $\"15+=+15\"$ \r
\n" ); document.write( "\n" ); document.write( "God bless you! ;)
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