document.write( "Question 409158: hi, I am solving by quadraic formula -b sqrt (b2-4ac)/(2a)\r
\n" ); document.write( "\n" ); document.write( "x^2+2x=168
\n" ); document.write( "x^2+2x-168=168-168
\n" ); document.write( "x^2+2x-168=0\r
\n" ); document.write( "\n" ); document.write( "-2 +- sqrt (2^2-4(1)(-168)/(2(1))
\n" ); document.write( "-2 +- sqrt (4-672)/(2)
\n" ); document.write( "-2 +- sqrt (668)/(2) This is where I am lost. It's not a perfect square, so
\n" ); document.write( " what do I do now? I choose factors.
\n" ); document.write( "-2 +- sqrt ((4(167))/(2)
\n" ); document.write( "-2 +- 2 sqrt (167)/(2)
\n" ); document.write( "common denominator of 2
\n" ); document.write( "-1 sqrt(167)/(2)\r
\n" ); document.write( "\n" ); document.write( "Would you help me understand where I went wrong and how to do it right?
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Algebra.Com's Answer #288088 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Sign Error:\r
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\n" ); document.write( "\n" ); document.write( "So it is a perfect square after all.\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it
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\"The

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