document.write( "Question 409110: Find three consecutive odd integers such that the sum of the first and the square of the last is 236. \n" ); document.write( "
Algebra.Com's Answer #288083 by Adrish(44)\"\" \"About 
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SOLUTIONS: Let the three consecutive odd integers are x,(x+2),(x+4)\r
\n" ); document.write( "\n" ); document.write( "Given:x+(x+4)^2 = 236\r
\n" ); document.write( "\n" ); document.write( "x+ x^2 +8x +16 = 236\r
\n" ); document.write( "\n" ); document.write( "x^2 +9x - 220 =0 \r
\n" ); document.write( "\n" ); document.write( "By solving the quadratic equation\r
\n" ); document.write( "\n" ); document.write( "x^2 + 20 x -11x -220 =0 \r
\n" ); document.write( "\n" ); document.write( "x(x+20) -11(x+20)=0
\n" ); document.write( "(x+20)(x-11)=0
\n" ); document.write( "x+20=0
\n" ); document.write( "and x-11=0\r
\n" ); document.write( "\n" ); document.write( "so x=-20 and x = 11\r
\n" ); document.write( "\n" ); document.write( "so the three consecutive integers are 11. 11+2, 11+4\r
\n" ); document.write( "\n" ); document.write( "11,13,15
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