document.write( "Question 409132: Find an equation of the parabola that has a focus at (9,15) and a vertex at (9,8) in terms of y. \n" ); document.write( "
Algebra.Com's Answer #288079 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
a focus at (9,15) and \r
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\n" ); document.write( "\n" ); document.write( "Since the \"x-coordinates\" of the \"vertex\" and \"focus\" are the \"same\", they are one of top of the other, so this is a \"regular\" vertical parabola, where the \"x+\"part is squared. \r
\n" ); document.write( "\n" ); document.write( "Since the vertex is \"below\" the focus, this is a \"right-side\"\"+up\" parabola and \"p+\"is positive. \r
\n" ); document.write( "\n" ); document.write( "Since the vertex and focus are 15 –8 = 7 units apart, then \"p+=+7\". \r
\n" ); document.write( "\n" ); document.write( "And that's all I need for my equation, since they already gave me the vertex.\r
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\n" ); document.write( "\n" ); document.write( " (x–h)^2=4p(y –k)\r
\n" ); document.write( "\n" ); document.write( " (x–9)^2 = 4*7(y –8)\r
\n" ); document.write( "\n" ); document.write( " (x–9)^2 = 28(y –8)\r
\n" ); document.write( "\n" ); document.write( " (x–9)^2/28= y–8
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\n" ); document.write( " (x–9)^2/28 +8= y \r
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\n" ); document.write( "\n" ); document.write( " \"y+=%28x%5E2-18x+%2B81%29%2F28+%2B8+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=%281%2F28%29x%5E2-0.64x+%2B2.9+%2B8+\"\r
\n" ); document.write( "\n" ); document.write( "\"y+=+%281%2F28%29x%5E2-0.64x+%2B10.9+\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+600%2C+600%2C+-35%2C+25%2C+-35%2C+25%2C+%281%2F28%29x%5E2-0.64x+%2B10.9%29+\"\r
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