document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=409071>Question 409071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What shape will the graph of y=xsquare+2 be? How can you tell. justify your prediction by making a table and graphing y=xsquare+2 on graph paper. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288049 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288049\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What shape will the graph of y=xsquare+2 be? How can you tell. justify your prediction by making a table and graphing y=xsquare+2 on graph paper.\r<BR>\n" );
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document.write( "y=x^2 is a parabola that opens upward (coefficient of x^2 is positive) with its vertex at (0,0)<BR>\n" );
document.write( "y=x^2+2 is the same parabola which is bumpt up 2 units.The graph below illustrates this. The parabola in red is the basic parabola and the parabola in green bumps it up 2 units.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2Cx%5E2%2B2%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+x%5E2%2Cx%5E2%2B2%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
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