document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=409074>Question 409074</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A small plastic pool has a diamter of 8.5 feet.  Find the area of the lawn that will be covered by the pool.  Use pie = 3.14. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #288047 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=288047\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A small plastic pool has a diamter of 8.5 feet. Find the area of the lawn that will be covered by the pool. Use pie = 3.14.<BR>\n" );
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document.write( "area = (pi)(d/2)^2<BR>\n" );
document.write( "where<BR>\n" );
document.write( "pi is 3.14<BR>\n" );
document.write( "d is diameter 8.5 feet<BR>\n" );
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document.write( "area = (3.14)(8.5/2)^2<BR>\n" );
document.write( "area = (3.14)(4.25)^2<BR>\n" );
document.write( "area = (3.14)(18.0625)<BR>\n" );
document.write( "area = 56.72 square feet\r<BR>\n" );
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document.write( " </SPAN>\n" );
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