document.write( "Question 408976: One candle will burn up completely in 4 hours, while a second candle of equal length requires 5 hours to burn up completely. If the candles are lit at the same time, how long will they burn before one is exactly three times as long as the other? \n" ); document.write( "
Algebra.Com's Answer #288038 by ankor@dixie-net.com(22740)\"\" \"About 
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One candle will burn up completely in 4 hours, while a second candle of equal
\n" ); document.write( " length requires 5 hours to burn up completely.
\n" ); document.write( " If the candles are lit at the same time, how long will they burn before one is
\n" ); document.write( " exactly three times as long as the other?
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\n" ); document.write( "Assign a value to the length of the candles, 20\"
\n" ); document.write( "then
\n" ); document.write( "\"20%2F4\" = 5 in/hr burn rate of candle 1
\n" ); document.write( "and
\n" ); document.write( "\"20%2F5\" = 4 in/hr burn rate of candle 2
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\n" ); document.write( "let t = time for candle 2 to be 3 times candle 1
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\n" ); document.write( "Candle 2 = 3 times candle 1
\n" ); document.write( "(20 - 4t) = 3(20 - 5t)
\n" ); document.write( "20 - 4t = 60 - 15t
\n" ); document.write( "-4t + 15t = 60 - 20
\n" ); document.write( "11t = 40
\n" ); document.write( "t = \"40%2F11\"
\n" ); document.write( "t = 3\"7%2F11\" hrs; 3 + \"7%2F11\"*60 = 38.2 min
\n" ); document.write( ":
\n" ); document.write( "3 hrs 38.2 min, Candle 2 will be three times the length of candle 1
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