document.write( "Question 408999: how can $54000 be invested part at 6% annual simple interest and the remainder at 12% annual simple intrest so that the intrest earned by the two acoounts will be equal? \n" ); document.write( "
Algebra.Com's Answer #288036 by checkley79(3341)\"\" \"About 
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.12X=.06(54,000-X)
\n" ); document.write( ".12X=3,240-.06X
\n" ); document.write( ".12X+.06X=3240
\n" ); document.write( ".18X=3,240
\n" ); document.write( "X=3,240/.18
\n" ); document.write( "X=18,000 IS THE AMOUNT INVESTED @ 12%
\n" ); document.write( "54,000-18,000=36,000 IS THE AMOUNT INVESTED @ 6%
\n" ); document.write( "PROOF:
\n" ); document.write( ".12*18,000=.06*36,000
\n" ); document.write( "2,160=2,160
\n" ); document.write( "
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