document.write( "Question 408999: how can $54000 be invested part at 6% annual simple interest and the remainder at 12% annual simple intrest so that the intrest earned by the two acoounts will be equal? \n" ); document.write( "
Algebra.Com's Answer #288036 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! .12X=.06(54,000-X) \n" ); document.write( ".12X=3,240-.06X \n" ); document.write( ".12X+.06X=3240 \n" ); document.write( ".18X=3,240 \n" ); document.write( "X=3,240/.18 \n" ); document.write( "X=18,000 IS THE AMOUNT INVESTED @ 12% \n" ); document.write( "54,000-18,000=36,000 IS THE AMOUNT INVESTED @ 6% \n" ); document.write( "PROOF: \n" ); document.write( ".12*18,000=.06*36,000 \n" ); document.write( "2,160=2,160 \n" ); document.write( " |