document.write( "Question 409017: write the equation of the line in slope intercept form perpendicular to y=2/3x+6 through (6,5) \n" ); document.write( "
Algebra.Com's Answer #288032 by clarkp(14)![]() ![]() You can put this solution on YOUR website! hello!!!\r \n" ); document.write( "\n" ); document.write( "with the given equation which is y=2/3x+6 identify first the slope.the slope of that equation is....m= 2/3.\r \n" ); document.write( "\n" ); document.write( "By then you had already identify use the formula \"point slope form\"\r \n" ); document.write( "\n" ); document.write( "y-y(sub1)=m(x-xsub1). \n" ); document.write( "now substitute. the pints that was give is (6,5) \n" ); document.write( "y-5=2/3(x-6) \n" ); document.write( "y-5=2/3x-12/3 \n" ); document.write( "y-5=(2/3)x-4 multiply both sides by 3 . \n" ); document.write( " 3(y-5)=3(2/3)x-4)3now distribute. \n" ); document.write( "3y-15=2x-12 make it to general form. \n" ); document.write( "-2x+3y-15+12=0 \n" ); document.write( "-2x+3y-3=0, in equation A must not be negative. To make the A positive ,multiply negative 1. \n" ); document.write( "so the result the equation of the line is 2x-3y+3=0. \n" ); document.write( " |