document.write( "Question 408877: (20x^4-3x^3=11x^2-7x+12)÷(4x-3)
\n" ); document.write( "Write your answer in the form Q(x)+(R(x))/(4x-3) , where Q(x) is the quotient and R(x) is the remainder of the division.\r
\n" ); document.write( "\n" ); document.write( " My answer shows this (20x^4-3x^3+11x^2-7x+12)/(4x-3)= this is blank + ?/4x-3 \n" ); document.write( "

Algebra.Com's Answer #288031 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!

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document.write( "       5x^3 +  3x^2 +  5x   +  2\r\n" );
document.write( "      _______________________________\r\n" );
document.write( "4x-3 /20x^4 -  3x^3 + 11x^2 - 7x + 12\r\n" );
document.write( "      20x^4 - 15x^3\r\n" );
document.write( "      -----------\r\n" );
document.write( "              12x^2 + 11x^2\r\n" );
document.write( "              12x^2 -  9x^2\r\n" );
document.write( "              -------------\r\n" );
document.write( "                      20x^2 -  7x\r\n" );
document.write( "                      20x^2 - 15x\r\n" );
document.write( "                      -----------\r\n" );
document.write( "                               8x + 12\r\n" );
document.write( "                               8x -  6\r\n" );
document.write( "                               -------\r\n" );
document.write( "                                    18\r\n" );
document.write( "

\n" ); document.write( "The remainder is 18 and the quotient is 5x^3 + 3x^2 + 5x + 2.
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