document.write( "Question 43871: Can anyone give me some help with this? I need the steps and solution:\r
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\n" ); document.write( "\n" ); document.write( "Factor completely\r
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\n" ); document.write( "\n" ); document.write( "-3t³ + 3t² - 6t
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Algebra.Com's Answer #28803 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Factor completely:
\n" ); document.write( "\"-3t%5E3%2B3t%5E2-6t\" First look for a factor that is common to each term. It looks like -3t is a common factor so factor this out.
\n" ); document.write( "\"-3t%28t%5E2-t%2B2%29\" Now see if the factor inside the parentheses is factorable.
\n" ); document.write( "Assume the factors will be:\"%28t%2Ba%29%28t%2Bb%29\"
\n" ); document.write( "Can you find a & b such that:
\n" ); document.write( "a*b = 2 and a + b = -1\r
\n" ); document.write( "\n" ); document.write( "The factors of 2 are:
\n" ); document.write( "(1)(2) or
\n" ); document.write( "(-1)(-2)\r
\n" ); document.write( "\n" ); document.write( "Neither of these pairs will add up to -1.\r
\n" ); document.write( "\n" ); document.write( "So I would conclude that you cannot factor the expression any further than:\r
\n" ); document.write( "\n" ); document.write( "\"-3t%5E3%2B3t%5E2-6t+=+-3t%28t%5E2-t%2B2%29\"
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