document.write( "Question 409020: Please help with solving these inequalities! They're SO confusing to me! I know you have to flip the inequality when it's a negative or something like that, but i just don't know how to go about it!\r
\n" ); document.write( "\n" ); document.write( "1) -1 > -x + 3
\n" ); document.write( "2) -7 - 2m >(or equal to)-9
\n" ); document.write( "3) a
\n" ); document.write( " --- <(or equal to)9
\n" ); document.write( " -3
\n" ); document.write( "Thanks if you can help! :) \n" ); document.write( "
Algebra.Com's Answer #288027 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
1) -1 > -x + 3 subtract 3.
\n" ); document.write( "-1-3>-x add the left side.
\n" ); document.write( "-4>-x divide by -1
\n" ); document.write( "4\n" ); document.write( "Proof:
\n" ); document.write( "Let x=4.1
\n" ); document.write( "-1>-4.1+3
\n" ); document.write( "-1>-1.1\r
\n" ); document.write( "\n" ); document.write( "2) -7 - 2m >=-9 add seven.
\n" ); document.write( "-2n>=-9+7 add the right side.
\n" ); document.write( "-2n>=-2 divide by -2
\n" ); document.write( "n<=-2/-2
\n" ); document.write( "n<=1 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "-7-2*1>=-9
\n" ); document.write( "-7-2>=-9
\n" ); document.write( "-9>=-9\r
\n" ); document.write( "\n" ); document.write( "3) a
\n" ); document.write( " --- <=9
\n" ); document.write( " -3
\n" ); document.write( " cross multiply:
\n" ); document.write( "a>=9*-3
\n" ); document.write( "a>=-27 ans.
\n" ); document.write( "Proof:
\n" ); document.write( "-27/-3<=9
\n" ); document.write( "9>=9
\n" ); document.write( " \n" ); document.write( "
\n" );