document.write( "Question 408972: How to solve 4^2x=32^1/2 \n" ); document.write( "

Algebra.Com's Answer #288009 by Coyote 10(7) $\"\"$ $\"About$

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First Convert 2^4x to (2^2)^2x and convert 32^1/2 to (2^5)(1/2). distribute 2x to the (2^2) to yield 2^4x and distribute 1/2 to 2^5 to yield 2^5/2. Thus your problem would become 2^4x=2^5/2. Because you have common bases you can simplify your problem to 4x=5/2. divide both sides by four and your answer would be 5/8 \n" ); document.write( "

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