document.write( "Question 408969: An automobile radiator contains 16 quarts of a 20% solution of antifreeze. How much of the orginal solution must be drained off and replaced by pure antifreeze to make a 25% solution of antifreeze? \n" ); document.write( "
Algebra.Com's Answer #288001 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Let x represent the amount drained off and replaced
\n" ); document.write( "Question states***
\n" ); document.write( " .20(16qt-x) + 1*x = .25*16qt
\n" ); document.write( "Solving for x
\n" ); document.write( " .8x = .05*16qt
\n" ); document.write( " x = 1qt, needs to be drained off and replaced with pure antifreeze\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***
\n" ); document.write( " .20*15 + 1 = 4 = .25*16 \n" ); document.write( "
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