document.write( "Question 408332: cube root (x^2y^4) x cube root (x^4y^10)\r
\n" ); document.write( "\n" ); document.write( "i got : x^2 cube root(y^10) is this correct
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Algebra.Com's Answer #287992 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
Please don't use \"x\" for multiplication. Use the word \"times\" or use \"*\" (Shift+8).

\n" ); document.write( "\"root%283%2C+x%5E2y%5E4%29+%2A+root%283%2C+x%5E4y%5E10%29\"
\n" ); document.write( "Your answer, \"x%5E2%2Aroot%283%2C+y%5E10%29\" is correct so far but it is unfinished. There is more simplifying we can do with the remaining cube root.

\n" ); document.write( "\"y%5E10\" is not a perfect cube. (Variables are perfect cubes if their exponents are multiples of 3.) But it does have perfect cube factors. Factoring the \"y%5E10\" into as many perfect cube factors as possible we get:
\n" ); document.write( "\"x%5E2%2Aroot%283%2C+y%5E3%2Ay%5E3%2Ay%5E3%2Ay%29\"
\n" ); document.write( "Now we can use a property of radicals, \"root%28a%2C+p%2Aq%29+=+root%28a%2C+p%29%2Aroot%28a%2C+q%29\" to separate the factors inside the cube root into separate cube roots:
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\n" ); document.write( "The cube roots of the perfect cubes will simplify:
\n" ); document.write( "\"x%5E2%2Ay%2Ay%2Ay%2Aroot%283%2C+y%29\"
\n" ); document.write( "which simplifies to:
\n" ); document.write( "\"x%5E2%2Ay%5E3%2Aroot%283%2C+y%29\"
\n" ); document.write( "This is the fully simplified expression.
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