document.write( "Question 408916: Solve by substitution method
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document.write( "y=40+0.25x
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document.write( "y=35+0.30x
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Algebra.Com's Answer #287989 by ilovezvezda(1)![]() ![]() ![]() You can put this solution on YOUR website! Solve by substitution method \n" ); document.write( "y=40+0.25x \n" ); document.write( "y=35+0.30x\r \n" ); document.write( "\n" ); document.write( "from the first equation, y-40/.25=x \n" ); document.write( "now substitute x in the 2nd equation with this value to find y \n" ); document.write( "y=35+.30(y-40/.25) (I'll now write .25 as 1/4 in the denominator) \n" ); document.write( "y=35+.30(4y-160) (to get rid of the decimal, we'll multiply both sides with 10) \n" ); document.write( "10y=350+3(4y-160) \n" ); document.write( "10y=350+12y-480 \n" ); document.write( "group y's in one side \n" ); document.write( "2y=130 \n" ); document.write( "y=65 \n" ); document.write( "from this, plug in the value of y in any of the equations to find the value of x. \n" ); document.write( " |