document.write( "Question 408916: Solve by substitution method
\n" ); document.write( "y=40+0.25x
\n" ); document.write( "y=35+0.30x
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Algebra.Com's Answer #287989 by ilovezvezda(1)\"\" \"About 
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Solve by substitution method
\n" ); document.write( "y=40+0.25x
\n" ); document.write( "y=35+0.30x\r
\n" ); document.write( "\n" ); document.write( "from the first equation, y-40/.25=x
\n" ); document.write( "now substitute x in the 2nd equation with this value to find y
\n" ); document.write( "y=35+.30(y-40/.25) (I'll now write .25 as 1/4 in the denominator)
\n" ); document.write( "y=35+.30(4y-160) (to get rid of the decimal, we'll multiply both sides with 10)
\n" ); document.write( "10y=350+3(4y-160)
\n" ); document.write( "10y=350+12y-480
\n" ); document.write( "group y's in one side
\n" ); document.write( "2y=130
\n" ); document.write( "y=65
\n" ); document.write( "from this, plug in the value of y in any of the equations to find the value of x.
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