document.write( "Question 408934: I am looking for some hep on this algebra problem for my child please. \r
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document.write( "Please show work: The Connecticut River flows at a rate of 4km/h for the length of a popular senic route. In order for a cruiser to travel 60 km upriver and then return in a total of 8 hr, how fast must the boat be able to travel in still water? \n" );
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Algebra.Com's Answer #287988 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! The Connecticut River flows at a rate of 4km/h for the length of a popular senic route. In order for a cruiser to travel 60 km upriver and then return in a total of 8 hr, how fast must the boat be able to travel in still water? \n" ); document.write( ". \n" ); document.write( "applying the distance formula: \n" ); document.write( "d = rt \n" ); document.write( "solving for time (t) we get: \n" ); document.write( "t = d/r \n" ); document.write( ". \n" ); document.write( "Let x = speed in still water \n" ); document.write( "then \n" ); document.write( "\"time upstream\" + \"time downstream\" = \"total time\" \n" ); document.write( ". \n" ); document.write( "60/(x-4) + 60/(x+4) = 8 \n" ); document.write( "multiplying both sides by (x-4)(x+4) we get: \n" ); document.write( "60(x+4) + 60(x-4) = 8(x-4)(x+4) \n" ); document.write( "60x+240 + 60x-240 = 8(x^2-16) \n" ); document.write( "120x = 8x^2-128 \n" ); document.write( "0 = 8x^2-120x-128 \n" ); document.write( "dividing both sides by 8: \n" ); document.write( "0 = x^2-15x-16 \n" ); document.write( "factoring: \n" ); document.write( "0 = (x-16)(x+1) \n" ); document.write( "x = {16,-1} \n" ); document.write( "we can throw out the negative solution leaving: \n" ); document.write( "x = 16 mph\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |