document.write( "Question 43872: Can anyone offer steps and solution for this one?\r
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\n" ); document.write( "\n" ); document.write( "Factor each polynomial. If the polynomial is prime, say so. \r
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\n" ); document.write( "\n" ); document.write( "18z + 45 + z²
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Algebra.Com's Answer #28798 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let's see if the expression can be factored. Rewrite it in standard form:
\n" ); document.write( " $\"z%5E2%2B18z%2B45\"$
\n" ); document.write( "The factors will look like: (z+a)(z+b) and you would like to have:
\n" ); document.write( "a*b = 45 and
\n" ); document.write( "a+b = 18\r
\n" ); document.write( "\n" ); document.write( "The factors of the first term are $\"z%2Az+=+z%5E2\"$
\n" ); document.write( "The possible factors (a & b) of the last term are:
\n" ); document.write( "3*15 = 45
\n" ); document.write( "5*9 = 45\r
\n" ); document.write( "\n" ); document.write( "Now you want the factors (a & b) of the last term to add up to 18 (a+b = 18) so you can get the middle term of your original expression (18z).
\n" ); document.write( "It looks like 3+15 = 18, so a = 3 and b = 15
\n" ); document.write( "So the factors of:
\n" ); document.write( " $\"z%5E2%2B18z%2B45+=+%28z%2B3%29%28z%2B15%29\"$ \r
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