document.write( "Question 408898: If the golden ration is 8 to 5. If the length of a rectangular painting is 2ft longer than its width, then for what dimensions would the length and width have the golden ratio? \n" ); document.write( "

Algebra.Com's Answer #287975 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and (x+2ft)represent the width and length respecitively
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document.write( " for what dimensions would the length and width have the golden ratio of 8/5
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document.write( "   |cross multiplying to solve for x
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document.write( "      8x = 5(x+2)
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document.write( "      3x = 10
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document.write( "       x = 10/3 ft, the width.  The length 16/3 ft\r
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