document.write( "Question 408907: Suppose that one solution contains 20% alcohol and another solution contains 50% alcohol. How many liters of each solution should be mixed to make 4.5 liters of a 40%-alcohol solution? \n" ); document.write( "

Algebra.Com's Answer #287973 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi
\n" );
document.write( "Let x and (4.5-x)represent the amount of the 50% and 20% solution respectively
\n" );
document.write( "Question states***
\n" );
document.write( "  .50x + .20(4.5 -x) = .40*4.5L
\n" );
document.write( "Solving for x
\n" );
document.write( "     .30x = .20*4.5L
\n" );
document.write( "Will let You finish it up \n" );
document.write( "

\n" );