document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408865>Question 408865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the best way to solve 13x-49=-179 how do i find x thank you<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287951 by </B><A HREF=/tutors/aboutme.mpl?userid=Adrish><B>Adrish(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adrish><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287951\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SOLUTIONS:<BR>\n" );
document.write( "Here we have the variable \"x\" so we need to find the value of \"x\".\r<BR>\n" );
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document.write( "13x-49=-179<BR>\n" );
document.write( " Now we need to isolate the x on one side and keep the constant terms at another side.\r<BR>\n" );
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document.write( "As we know the opposite of subtraction is addition.\r<BR>\n" );
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document.write( "we will add 49 on both sides of the equation\r<BR>\n" );
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document.write( "13x -49 + 49= -179 +49<BR>\n" );
document.write( "13x=-130<BR>\n" );
document.write( "x = -130/13<BR>\n" );
document.write( "x=-10 </SPAN>\n" );
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