document.write( "Question 408847: Solve the following expression using a common base:
\n" ); document.write( "(1/2)^(4x+1)=(1/4)^(3x+3)
\n" ); document.write( "I figured that I could turn 1/2 into (1/4)^2, (you end up with x=1/5), but LS does not equal RS with x=1/5 \r
\n" ); document.write( "\n" ); document.write( "here's what I tried:
\n" ); document.write( "(1/2)^(4x+1)=(1/4)^(3x+3)
\n" ); document.write( "(1/4)^2(4x+1)=(1/4)^(3x+3)
\n" ); document.write( "(1/4)^(8x+2)=(1/4)^(3x+3)\r
\n" ); document.write( "\n" ); document.write( "8x+2=3x+3
\n" ); document.write( "8x-3x=3-2
\n" ); document.write( "5x=1
\n" ); document.write( "x=(1/5)\r
\n" ); document.write( "\n" ); document.write( "LS:
\n" ); document.write( "=(1/2)^(4x+1)
\n" ); document.write( "=(1/2)^(4(1/5)+1)
\n" ); document.write( "=(1/2)^1.8
\n" ); document.write( "=0.287\r
\n" ); document.write( "\n" ); document.write( "RS:
\n" ); document.write( "=(1/4)^(3x+3)
\n" ); document.write( "=(1/4)^(3(1/5)+3)
\n" ); document.write( "=(1/4)^(3.6)
\n" ); document.write( "=0.0068\r
\n" ); document.write( "\n" ); document.write( "LS does not equal RS, so I'm oviously wrong...\r
\n" ); document.write( "\n" ); document.write( "I'd truly appreciate any help I could get!! Thank You :) \n" ); document.write( "

Algebra.Com's Answer #287928 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


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document.write( "Hi
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document.write( "Solving the following expression using a 'common base':
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document.write( "(1/2)^(4x+1)=(1/4)^(3x+3) 
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document.write( "(1/2)^(4x+1)=(1/2)^2(3x+3)
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document.write( "     4x+ 1 = 2(3x+3)
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document.write( "     4x+ 1 = 6x+6
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document.write( "         -5 = 2x
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document.write( "        -5/2 = x 
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document.write( "CHECKING our Answer***
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document.write( "(1/2)^-9 = (1/4)^(-9/2)= (1/2)^-9 \n" );
document.write( "

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