document.write( "Question 408843: Annyeong!!
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document.write( "I need your help,please help me to answer this.\r
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document.write( "Ivy is 8 years older than Beverly. Three years ago,Beverly was 2 years more than one-third as old as Ivy was then. How old is Ivy now?\r
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document.write( "Kamsahamnida^^ \n" );
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Algebra.Com's Answer #287925 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! Let assume Beverly age = x then Ivy age = x+8 years.\r \n" ); document.write( "\n" ); document.write( "3 years ago, Beverly age = x-3 , Ivy age = x+8-3 = x+5 \r \n" ); document.write( "\n" ); document.write( "according to question, \r \n" ); document.write( "\n" ); document.write( " x-3 = (x+5)/3 + 2 ........ [2 years more than one-third of Ivy age]\r \n" ); document.write( "\n" ); document.write( "=> x-5 = (x+5)/3 \r \n" ); document.write( "\n" ); document.write( "=> 3(x-5) = x+5\r \n" ); document.write( "\n" ); document.write( "=> 3x -15 = x +5 \r \n" ); document.write( "\n" ); document.write( "=> 3x -x = 5 + 15 \r \n" ); document.write( "\n" ); document.write( "=> x= 20/2 = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "present age of Beverly is 10 years, \r \n" ); document.write( "\n" ); document.write( "Ivy age = 10+8 = 18 years.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |