document.write( "Question 408841: Annyeong Haseyo~Can you help me?..\r
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document.write( "Ivy is 8 years older than Beverly. Three years ago,Beverly was 2 years more than one-third as old as Ivy was then. How old is Ivy now?\r
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document.write( "Kamsahamnida!! I= 12+(1/3)I B= 5+(1/3)(I-3) \n" );
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Algebra.Com's Answer #287923 by bobbyjoebob(2)![]() ![]() You can put this solution on YOUR website! Ivy is 8 years old because \n" ); document.write( "I=B+8 \n" ); document.write( "B-3=2+[1/3(I-3)]\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Beverly - 3 because it says three years ago \n" ); document.write( "and same with Ivy - 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so it's one third (I-3) which makes it\r \n" ); document.write( "\n" ); document.write( "[(1/3)I - 1] + 2 = B - 3\r \n" ); document.write( "\n" ); document.write( "[(1/3)I - 1] + 5 = B\r \n" ); document.write( "\n" ); document.write( "Plug into other equation: \r \n" ); document.write( "\n" ); document.write( "\"[B+8=I]\" so it's\r \n" ); document.write( "\n" ); document.write( "[[(1/3)I - 1] + 5] + 8 = I\r \n" ); document.write( "\n" ); document.write( "then solve\r \n" ); document.write( "\n" ); document.write( "12 + [1/3]I = I \n" ); document.write( "12 = 2/3 I \n" ); document.write( "[3/2]12 = [3/2](2/3)I \n" ); document.write( "8 = I\r \n" ); document.write( "\n" ); document.write( "I- Ivy \n" ); document.write( "B- Beverly \n" ); document.write( " |