document.write( "Question 408841: Annyeong Haseyo~Can you help me?..\r
\n" ); document.write( "\n" ); document.write( "Ivy is 8 years older than Beverly. Three years ago,Beverly was 2 years more than one-third as old as Ivy was then. How old is Ivy now?\r
\n" ); document.write( "\n" ); document.write( "Kamsahamnida!! I= 12+(1/3)I B= 5+(1/3)(I-3)
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Algebra.Com's Answer #287923 by bobbyjoebob(2)\"\" \"About 
You can put this solution on YOUR website!
Ivy is 8 years old because
\n" ); document.write( "I=B+8
\n" ); document.write( "B-3=2+[1/3(I-3)]\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " Beverly - 3 because it says three years ago
\n" ); document.write( "and same with Ivy - 3\r
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\n" ); document.write( "\n" ); document.write( "so it's one third (I-3) which makes it\r
\n" ); document.write( "\n" ); document.write( "[(1/3)I - 1] + 2 = B - 3\r
\n" ); document.write( "\n" ); document.write( "[(1/3)I - 1] + 5 = B\r
\n" ); document.write( "\n" ); document.write( "Plug into other equation: \r
\n" ); document.write( "\n" ); document.write( "\"[B+8=I]\" so it's\r
\n" ); document.write( "\n" ); document.write( "[[(1/3)I - 1] + 5] + 8 = I\r
\n" ); document.write( "\n" ); document.write( "then solve\r
\n" ); document.write( "\n" ); document.write( "12 + [1/3]I = I
\n" ); document.write( "12 = 2/3 I
\n" ); document.write( "[3/2]12 = [3/2](2/3)I
\n" ); document.write( "8 = I\r
\n" ); document.write( "\n" ); document.write( "I- Ivy
\n" ); document.write( "B- Beverly
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