document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408806>Question 408806</A>: <I><SPAN STYLE=\"word-break: break-all;\"> log(base 3)(x-5)+ log(base 3)(x+3)=2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287918 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x - 5)(x + 3) = 9\r<BR>\n" );
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document.write( "x^2 - 2x - 24 = 0\r<BR>\n" );
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document.write( "factoring ___ (x - 6)(x + 4) = 0\r<BR>\n" );
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document.write( "HINT : logarithms are not defined for negative arguments , so only one of the factored solutions is correct </SPAN>\n" );
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