document.write( "Question 408507: solve for x. log(2)^x=8+9log(x)^2 \n" ); document.write( "

Algebra.Com's Answer #287912 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
It is very difficult to understand what your equation is. Is it
\n" ); document.write( " $\"+log%28%282%5Ex%29%29=8%2B9log%28%28x%5E2%29%29+\"$
\n" ); document.write( "or
\n" ); document.write( " $\"+%28log%28%282%29%29%29%5Ex+=+8+%2B+9%28log%28%28x%29%29%29%5E2\"$
\n" ); document.write( "or
\n" ); document.write( " $\"+log%282%2C+%28x%29%29+=+8+%2B+9log%28x%2C+%282%29%29+\"$
\n" ); document.write( "or something else?

\n" ); document.write( "Tutors are more likely to help when the problem is clearly stated. Logarithmic expressions can be particularly difficult. With logarithms I suggest you learn how to read them and then post them in part English and part Math terms. For example,
\n" ); document.write( " $\"log%283%2C+%28x%2By%29%29\"$
\n" ); document.write( "is the \"base 3 log of (x+y)\". Note the use of parentheses. The \"base 3 log of x + y\" would be:
\n" ); document.write( " $\"log%283%2C+%28x%29%29+%2B+y\"$
\n" ); document.write( "which is not the same thing.

\n" ); document.write( "BTW, if your equation was
\n" ); document.write( " $\"+log%282%2C+%28x%29%29+=+8+%2B+9log%28x%2C+%282%29%29+\"$
\n" ); document.write( "(or something close to it), then there are no exponents in this equation!. This equation is \"the base 2 log of x = 8 + 9 times the base x log of 2\". \n" ); document.write( "

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