document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43879>Question 43879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use log(5) 2&#8776;0.4307 and log(5) 3&#8776;0.6826 to approximate the value of log(5) 12.\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28791 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28791\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use log(5) 2&#8776;0.4307 and log(5) 3&#8776;0.6826 to approximate the value of log(5) 12.\r<BR>\n" );
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document.write( "Log(5)12 = Log(5)[3*2^2] = log(5)3 + 2log(5)2<BR>\n" );
document.write( "=0.4307 +2(0.6826)<BR>\n" );
document.write( "=1.7959\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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