document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408774>Question 408774</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a ectangle is twice the width. The area is 722yd^2. Find the lenght and the width.\r<BR>\n" );
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document.write( "The length?______\r<BR>\n" );
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document.write( "the width?_______<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287903 by </B><A HREF=/tutors/aboutme.mpl?userid=Adrish><B>Adrish(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Adrish><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> SOLUTION: Let L be the length and W be the width of a rectangle.\r<BR>\n" );
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document.write( "Given: L= 2W and Area= 722 yd square\r<BR>\n" );
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document.write( "We Know  Area= L x W\r<BR>\n" );
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document.write( "         722 = 2W x W<BR>\n" );
document.write( "         722 = 2W^2<BR>\n" );
document.write( "         722/2 = W^2<BR>\n" );
document.write( "         361 = W^2<BR>\n" );
document.write( "        Width(W)= 19 Yard\r<BR>\n" );
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document.write( "Therefore Length(L) = 2W<BR>\n" );
document.write( "                    = 2 x 19   \r<BR>\n" );
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document.write( "                    =38 Yard </SPAN>\n" );
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