document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408765>Question 408765</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please show me how to solve this problem? -2|3x-4|<16\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287891 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you divide both sides of the inequality by -2 you'll get \r<BR>\n" );
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document.write( "|3x-4| > -8\r<BR>\n" );
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document.write( "Note: remember that the sign will flip when you divide both sides by a negative number.\r<BR>\n" );
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document.write( "Now remember that the absolute value of ANY number is ALWAYS nonnegative. In other words, it will NEVER be negative.\r<BR>\n" );
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document.write( "Since 0 and every positive number is greater than any negative number, this means that the inequality |3x-4| > -8 is true for ALL values of x.\r<BR>\n" );
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document.write( "So there are an infinite number of solutions. Basically, any real number will work for x.\r<BR>\n" );
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document.write( "Jim<BR>\n" );
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