document.write( "Question 408764: Liz drove the first half of a trip at 36 mi/h. At what speed should she cover the remaining half in order to average 45 mi/h for the whole trip \n" ); document.write( "
Algebra.Com's Answer #287890 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Liz drove the first half of a trip at 36 mi/h. At what speed should she cover the remaining half in order to average 45 mi/h for the whole trip \n" ); document.write( "----- \n" ); document.write( "1st half DATA: \n" ); document.write( "distance = x miles ; rate = 36 mph ; time = x/36 hrs. \n" ); document.write( "---- \n" ); document.write( "Whole trip DATA: \n" ); document.write( "distance = 2x miles ; rate = 45 mph ; time = 2x/45 hrs \n" ); document.write( "-------------------- \n" ); document.write( "2nd half DATA: \n" ); document.write( "distance = x miles; \n" ); document.write( "time = (2x/45)-(x/36) = (72x-45x)/(45*36) \n" ); document.write( "= 27x/(45*36) = x/(5*12) = x/60 hrs \n" ); document.write( "rate = d/t = x/(x/60) = 60 mph \n" ); document.write( "================================== \n" ); document.write( "Ans: 60 mph \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========== \n" ); document.write( " |