Algebra.Com's Answer #28789 by stanbon(75887)  You can put this solution on YOUR website! Determine the vertex of y=x^2-8x+22. Thank you!\r \n" );
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document.write( "Put the equation in vertex form by completing the square, as follows:\r \n" );
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document.write( "y-22=x^2-8x \n" );
document.write( "y-22+16=x^2-8x+4^2 \n" );
document.write( "y-6=(x-4)^2\r \n" );
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document.write( "Vertex is at (4,6). \n" );
document.write( "This is what it looks like. \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation with variable | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " The discriminant -24 is less than zero. That means that there are no solutions among real numbers.
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document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
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document.write( " In the field of imaginary numbers, the square root of -24 is + or - . \n" );
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document.write( " The solution is  \n" );
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document.write( " Here's your graph: \n" );
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document.write( "Cheers, \n" );
document.write( "Stan H. \n" );
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