document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408579>Question 408579</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the product rule with g = f to show that if f is differentiable, then \r<BR>\n" );
document.write( "\n" );
document.write( "d/dx[f(x)]^2 = 2f(x)f'(x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287887 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since f(x)^2 = f(x)f(x), we can take the derivative using the Product rule to obtain:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "d/dx [f(x)f(x)] = f'(x)f(x) + f(x)f'(x) = 2f(x)f'(x). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );