document.write( "Question 408709: Hi,
\n" ); document.write( "I would like to know how to convert a log value back to its normal value. I looked up on the internet and found tat in can be done by (10^x), where x is the logarithmic value and the answer i get would be the actual value before applying the log.\r
\n" ); document.write( "\n" ); document.write( "Thanks in advance.\r
\n" ); document.write( "\n" ); document.write( "Harish.
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Algebra.Com's Answer #287862 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
If we have \"log%28a%2C+x%29\", then\r
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\n" ); document.write( "\n" ); document.write( "\"a%5E%28log%28a%2C+x%29%29+=+x\".
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