document.write( "Question 408325: You want to fill nine 1-lb tins with a holiday snack mix. You want the mix to contain the three following items: dried apple pieces which cost $2.45 per pound., pecans which cost $1.85 per pound, and dried cherry pieces which cost $0.80 per pound. You must spend $15 and want the mix to contain half as many pounds of cherry pieces as dried apple slices and pecans combined. How many pounds of pecans should you buy? \n" ); document.write( "
Algebra.Com's Answer #287857 by ankor@dixie-net.com(22740)\"\" \"About 
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You want to fill nine 1-lb tins with a holiday snack mix.
\n" ); document.write( " You want the mix to contain the three following items:
\n" ); document.write( "dried apple pieces which cost $2.45 per pound.,
\n" ); document.write( " pecans which cost $1.85 per pound,
\n" ); document.write( " and dried cherry pieces which cost $0.80 per pound.
\n" ); document.write( " You must spend $15 and want the mix to contain half as many pounds of cherry
\n" ); document.write( " pieces as dried apple slices and pecans combined.
\n" ); document.write( " How many pounds of pecans should you buy?
\n" ); document.write( ":
\n" ); document.write( "Let p = lbs of pecans required
\n" ); document.write( "Let a = lbs of apples
\n" ); document.write( "Let c = lbs of cherrys
\n" ); document.write( ":
\n" ); document.write( "a + p + c = 9
\n" ); document.write( ":
\n" ); document.write( "2.45a + 1.85p + .80c = 15
\n" ); document.write( ":
\n" ); document.write( "\"the mix to contain half as many pounds of cherry pieces as dried apple slices and pecans combined.
\n" ); document.write( ".5c = a + p
\n" ); document.write( "Rearrange as
\n" ); document.write( "a + p -.5c = 0
\n" ); document.write( "Subtract from the 1st equation
\n" ); document.write( "a + p + c = 9
\n" ); document.write( "a + p -.5c = 0
\n" ); document.write( "-----------------subtracting eliminates a & p, find c
\n" ); document.write( "1.5c = 9
\n" ); document.write( "c = \"9%2F1.5\"
\n" ); document.write( "c = 6 lb of cherries
\n" ); document.write( "then
\n" ); document.write( "a + p = .5(6)
\n" ); document.write( "a + p = 3
\n" ); document.write( "a = (3-p)
\n" ); document.write( ":
\n" ); document.write( "In the cost equation: replace a with (3-p), replace c with 6, find p
\n" ); document.write( "2.45(3-p) + 1.85p + .80(6) = 15
\n" ); document.write( "7.35 - 2.45p + 1.85p + 4.80 = 15
\n" ); document.write( "-2.45p + 1.85p + 12.15 = 15
\n" ); document.write( "-.60p = 15 - 12.15
\n" ); document.write( "-.6p = 2.85
\n" ); document.write( "p = \"2.85%2F%28-.6%29\"
\n" ); document.write( "p = -4.75, a negative means this problem has a major flaw in it. Can't be done with these values|\r
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