document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=408729>Question 408729</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At most, how much water can be evaporated from 300 liters of a 2% salt solution if the resulting solution is not to exceed 3% in salt content? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #287854 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=287854\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At most, how much water can be evaporated from 300 liters of a 2% salt solution if the resulting solution is not to exceed 3% in salt content?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "water - water = water<BR>\n" );
document.write( "0.98*300 - 1x = 0.97(300-x)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "98*300 - 100x = 97*300 - 97x<BR>\n" );
document.write( "3x = 300<BR>\n" );
document.write( "x = 100 liters (amt. of water to evaporate)<BR>\n" );
document.write( "========================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );