document.write( "Question 408682: Solve the following exponential equations using logarithms:\r
\n" ); document.write( "\n" ); document.write( "2^(x) = 3^(x+1)\r
\n" ); document.write( "\n" ); document.write( "Feeling pretty lost on this one...
\n" ); document.write( "I've tried to google for similar examples, but when I do find a similar problem it's solves using a form like this: \"xln(2)=(xln(3)+ln(3))\" I think this is a little beyond where I am now :( Looking for a more basic algebra solution! \r
\n" ); document.write( "\n" ); document.write( "Appreciate any help!!
\n" ); document.write( "Thanks :) \n" ); document.write( "
Algebra.Com's Answer #287853 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If something like \"xln(2)=(xln(3)+ln(3))\" scares you, then just replace each \"ln\" with \"log\" and you'll get\r
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\n" ); document.write( "\n" ); document.write( "xlog(2)=xlog(3)+log(3)\r
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\n" ); document.write( "\n" ); document.write( "Why can I replace \"ln\" with \"log\"? Because \"ln\" is actually a log that has base 'e' (2.718...). However you can use any log of any base. So you can use the default log of base 10 if you want.\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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